oblicz zawartosc procentowa pierwiastkow w kwasie propionowym

C2H5COOH mC=12u mH=1u mO=16u   mC2H5COOH=3*12+6*1+2*16=36+6+32=74 %pierwiastka=(mpierwiastka/mzwiazku)*100%   %c=(36/74)*100%=3600%/74=48,7% %H=(6/74)*100%=600%/74=8,1% %O=(32/74)*100%=3200/74=43,2%

mC2H5COOH=36u+6u+32u=74u %C = (36/74)*100% = 48,6% %H = (6/74)*100% = 8,2% %O = (32/74)*100% = 43,2%