wielomiany. Rozwiąż 1. x3+5x2+2x-8=0 2. x5-x4-5x3+5x2+6x-6=0 3. x3-x2+4x-4=0 4. 2x3-3x2+6x-5=0 5. x3-2x2+3x-2=0

1. x3 + 5x2 + 2x - 8 = 0 W (1) = 0   schemat HORNERA: 1 5 2 -8 1  1 6  8 1 6 8  0   (x-1)(x2 + 6x + 8) = 0 delta = 36 - 32 = 4; pierwiastek z delty = 2   x1 = (-6-2)/2 = -4 x2 = (-6 + 2)/2 = -2 (x-1)(x+4)(x+2) = 0 x=1 lub x=-4 lub x=-2   3. x3-x2+4x-4 = 0 x2(x-1) + 4(x-1) = 0 (x2 +4)(x-1) = 0 x=1