-2x2-24x+126=0 a= -2 b=-24 c=126 Δ=b2-4ac= (-24)2-4*(-2)*126= 576-1008= -432 Δ<0 brak rozwiązań x2+14x+24=0 a=1 b=14 c=24 Δ= b2-4ac= 142-4*1*24=196-96=100 Δ>0 x1=(-b-√Δ)/2a=(-14-√100)/(2*1)=(-24)/2= -12 x2=(-b+√Δ)/2a=(-14+√100)/(2*1)=(-4)/2= -2 1/2x2-1/2x-3=0 a= 1/2 b= - 1/2 c=-3 Δ= b2-4ac=(-1/2)2-4*(1/2)*(-3)= 1/4+6= 25/4 Δ>0 x1=(-b-√Δ)/2a=(1/2-√(25/4))/(2*(1/2))=(-2)/1= -2 x2=(-b+√Δ)/2a=(1/2 +√(25/4))/(2*(1/2))=3/1= 3 1/2x2+1/6x-1/9=0 a= 1/2 b=1/6 c=-1/9 Δ= b2-4ac=(1/6)2-4*(1/2)*(-1/9)= 1/36 + 4/18 = 1/36 + 8/36= 9/36 Δ>0 x1=(-b-√Δ)/2a= (1/6-√(9/36))/(2*(1/2)) = (- 2/6)/1= - 1/3 x2=(-b+√Δ)/2a=(1/6 +√(9/36))/(2*(1/2))=(4/6)/1= 4/6 PS: w 5 i 6 nie pamiętam jak się robiło tego typu zadania :) mam nadzieję że pomogłam :)
