Jutro bede musiala rozwiazac te zadania przy tablicy, wiec jeszcze dzis musze sie ich nauczyc. Podaje tresc, wyniki i wzory. Prosze o szybka pomoc, potrzebuje obliczenia do zadania 6.4 i 6.1   BLAGAM POMOCY! (Zdjecie w zalaczniku) 

z. 6,1 a) a1 = 5,  q = 2,  n = 6 Sn = a1*[ 1 - q ^n]/ [ 1 - q ] S6 = 5*[ 1 - 2 ^6]/[ 1 - 2] = 5*[ 1 - 64]/(-1) = -5 *(- 63) = 315 ===================================================== b) a1 = - 27,  q = 1/3 ,  n = 5 S5 = -27([1 - (1/3)^5]/[ 1 - 1/3] = - 27 *[ 1 - 1/243]/(2/3) = = - 27 *(3/2)*( 242/243) = (- 81/2)*( 242/243) = - 121/3 = - 40  1/3 =============================================================== c) a1 = 8,  q = 1, n = 10 S10 = n*a1 = 10* 8 = 80 ========================= d) a1 = 1/2,  q = - 1,  n = 100 S100 = (1/2)*[ 1- (-1)^100]/[ 1 - (-1)] = (1/2)*[ 1 - 1]/2 = (1/4)*0 = 0 ============================================================= e) a1 = - 64, q = - 2, n = 6 S6 = - 64*[ 1 - (- 2)^6] / [ 1 - (-2)] = - 64 *[1 - 64]/3 = - 64*(-63)/ 3 =  = 64*21 = 1344 ===============     z.6.4 a) a1 = - 3, q = 1/2, n = 5 S5 = -3*[ 1- (1/2)^5]/[ 1 - 1/2] = -3*[  1 - 1/32]/(1/2) = -3*2*(31/32) = = -93/16 = - 5  13/16 ======================= b) a1 = 10, q = - 2, Sn = 430 10*[1 - (-2)^n]/[ 1 - (-2)] = 430 / : 10 [ 1 - (-2)^n] / [ 1 +2] = 43 [ 1 - (-2)^n] = 43*3 = 129 - (-2)^n = 129 - 1 = 128 (-2)^n = - 128 n = 7 ============== c) a1 = - 5,  n = 3, Sn = - 15/4 -5*[ 1 - q^3]/ [ 1 - q] = - 15/4  dzielimy przez ( -5) [ 1 - q^3]/ [ 1 - q ] = 3/4 [ q^3 - 1]/[ q - 1] =  3/4 q^2 + q + 1 = 3/4  / * 4 4 q^2 + 4 q + 4 = 3 4 q^2 + 4 q + 1 = 0 delta = 4^2 - 4*4*1 = 0 q = -4/8 = - 1/2 =================== d) q = 3, n = 5, S5 = 121/2 a1*[ 1 - 3^5]/[ 1 - 3] = 121/2 a1*[ 1 - 243]/(- 2) = 121/2 a1*( - 242)/(-2) = 121/2 a1* 121 = 121/2 a1 = (121/2): 121= 1/2 ===============================