Zapisz w postaci potęgi o wykładniku naturalnym A) (-√3)⁻¹¹ B)( ×/√3)⁻¹³ C)( xy/√5)⁻¹⁴ D)(-³√5)⁻¹⁵ E)( x/-⁵√₇)⁻¹⁶ /-to jest kreska ułamkowa Oblicz A)(³√2)⁻³ B) (-√5)⁻⁴ C) (-³√3)⁻⁶

Zadanie 1 A) [latex](-sqrt{3})^{-11} = (-frac{1}{sqrt{3}})^{11} = (-frac{sqrt{3}}{3})^{11}[/latex] B) [latex](frac{x}{sqrt{3}})^{-13} = (frac{sqrt{3}}{x})^{13} \ x eq0[/latex] C) [latex](frac{xy}{sqrt{5}})^{-14} = (frac{sqrt{5}}{xy})^{14} \ xy eq 0[/latex] D) ([latex](-sqrt[3]{5})^{-15} = (-frac{1}{sqrt[3]{5}})^{15} = (-frac{sqrt[3]{25}}{5})^{15}[/latex] E) [latex](frac{x}{sqrt[5]{7}})^{-16} = (frac{sqrt[5]{7}}{x})^{16} \ x eq0[/latex]   Zadanie 2 A) [latex](sqrt[3]{2})^{-3} = (frac{1}{sqrt[3]{2}})^{3} = frac{1}{2}[/latex] B) [latex](-sqrt{5})^{-4} = (-frac{1}{sqrt{5}})^{4} = frac{1}{25}[/latex] C) [latex](-sqrt[3]{3})^{-6} = (-frac{1}{sqrt[3]{3}})^{6} = [(-frac{1}{sqrt[3]{3}})^{3}]^{2} = \ = (-frac{1}{3})^{2} = frac{1}{9}[/latex]