[latex]frac{m}{1}=frac{m_{o}}{sqrt{1-(frac{V}{c}})^{2}} \ na krzyz \ msqrt{1-(frac{V}{c}})^{2}=m_{0} \ sqrt{1-(frac{V}{c}})^{2}=frac{m_{0}}{m} \ [/latex] [latex] sqrt{1-(frac{V}{c}})^{2}=frac{m_{0}}{m} \ 1-frac{V^{2}}{c^{2}}=frac{m_{o}^{2}}{m^{2}} \ frac{V^{2}}{c^{2}}=1-frac{m_{o}^{2}}{m^{2}} \ V^{2}=c^{2}[1-frac{m_{o}^{2}}{m^{2}}][/latex] [latex]V^{2}=c^{2}[1-frac{m_{o}^{2}}{m^{2}}] \ V_{1}=csqrt{1-frac{m_{0}^{2}}{m^{2}}} \ V_{2}=-csqrt{1-frac{m_{0}^{2}}{m^{2}}}[/latex] są 2 rozwiązania ponieważ jest kwadrat przy V. [latex](V+V_{x}+V_{y})(m+m_{x}+m_{y}) + frac{(V+V_{x}+V_{y}(J_{o}+J_{x})}{r^{2}}=sqrt{2mgh} \ frac{(V+V_{x}+V_{y}(J_{o}+J_{x})}{r^{2}}=frac{sqrt{2mgh} - (V+V_{x}+V_{y})(m+m_{x}+m_{y}) }{1} \ [/latex] [latex] r^{2}[sqrt{2mgh} - (V+V_{x}+V_{y})(m+m_{x}+m_{y}) ]=(V+V_{x}+V_{y}(J_{o}+J_{x}) \ [/latex] [latex]r^{2}[sqrt{2mgh} - (V+V_{x}+V_{y})(m+m_{x}+m_{y}) ]=(V+V_{x}+V_{y}(J_{o}+J_{x}) \ \ r^{2}=frac{(V+V_{x}+V_{y}(J_{o}+J_{x})}{sqrt{2mgh} - (V+V_{x}+V_{y})(m+m_{x}+m_{y})}[/latex] [latex]r_{1}=-sqrt{frac{(V+V_{x}+V_{y}(J_{o}+J_{x})}{sqrt{2mgh} - (V+V_{x}+V_{y})(m+m_{x}+m_{y})}} \ r_{2}=sqrt{frac{(V+V_{x}+V_{y}(J_{o}+J_{x})}{sqrt{2mgh} - (V+V_{x}+V_{y})(m+m_{x}+m_{y})}}[/latex] są 2 rozwiązania bo jest kwadrat przy r
