a) x√2 = 4 /:√2 x=[latex]frac{4}{sqrt{2}}[/latex] pozbywamy się niewymierności z mianownika [latex]frac{4}{sqrt{2}}=frac{4}{sqrt{2}}cdot frac{{sqrt{2}}}{sqrt{2}}=frac{4sqrt{2}}{2}=2sqrt{2}[/latex] b)y√3 = √2 /: √3 y=[latex]frac{sqrt{2}}{sqrt{3}}=frac{sqrt{2}}{sqrt{3}}cdot frac{sqrt{3}}{sqrt{3}}=frac{sqrt{6}}{3}[/latex] c) y√7 + 2 = 5 y√7=3 /:√7 y=[latex]frac{3}{sqrt{7}}=frac{3}{sqrt{7}}cdot frac{sqrt{7}}{sqrt{7}}=frac{3sqrt{7}}{7}[/latex] d) 4 - √5x = 9 -√5x=5 /:√5 -x=[latex]frac{5}{sqrt{5}}=frac{5}{sqrt{5}}cdot frac{sqrt{5}}{sqrt{5}}=frac{5sqrt{5}}{5}=sqrt{5}[/latex] x=-[latex]sqrt{5}[/latex] e)[latex]frac{6}{y}=frac{sqrt2}{2}[/latex] mnoższ na krzyż [latex]ysqrt2=12 /:sqrt2[/latex] y=[latex]frac{12}{sqrt2}cdot frac{sqrt2}{sqrt2}=frac{12sqrt2}{2}=6sqrt2[/latex] x∛3 = 4/:∛3 x=[latex]frac{4}{sqrt[3]{3}}=frac{4}{sqrt[3]{3}}cdotfrac{sqrt[3]{3^2}}{sqrt[3]{3^2}}=frac{4sqrt[3]{9}}{3}[/latex]
