Zapisz wyrażenia w prostszej postaci:   a) [latex]sqrt{32} +5sqrt{2} - sqrt{200} + sqrt{2}[/latex]   b) [latex]frac{sqrt{2} + 3sqrt{8}- sqrt{18}}{sqrt{2}}[/latex]   c) [latex]sqrt{24} * sqrt{3}[/latex]   d) [latex]4sqrt{3} + sqrt{27}[/latex]

Zapisz wyrażenia w prostszej postaci:   a) [latex]sqrt{32} +5sqrt{2} - sqrt{200} + sqrt{2}[/latex]   b) [latex]frac{sqrt{2} + 3sqrt{8}- sqrt{18}}{sqrt{2}}[/latex]   c) [latex]sqrt{24} * sqrt{3}[/latex]   d) [latex]4sqrt{3} + sqrt{27}[/latex]
Odpowiedź

a)   [latex]sqrt{32}+5sqrt{2}-sqrt{200}+sqrt{2}=sqrt{16cdot2}+5sqrt2-sqrt{100cdot2}+sqrt2=\=4sqrt2+5sqrt2-10sqrt2+sqrt2=0[/latex]   b)   [latex]frac{sqrt{2}+3sqrt{8}-sqrt{18}}{sqrt{2}}=frac{sqrt2+3sqrt{4cdot2}-sqrt{9cdot2}}{sqrt2}=frac{sqrt2+3cdot2sqrt2-3sqrt2}{sqrt2}=\=frac{-2sqrt2+6sqrt2}{sqrt2}=frac{4sqrt2}{sqrt2}=4[/latex]   c)   [latex]sqrt{24}cdotsqrt{3}=sqrt{24cdot3}=sqrt{72}=sqrt{36cdot2}=6sqrt2[/latex]   d)   [latex]4sqrt{3}+sqrt{27}=4sqrt3+sqrt{9cdot3}=4sqrt3+3sqrt3=7sqrt3[/latex]    

a)=4√2+5√2-10√2+√2=0 b)=(√2+6√2-3√2)/√2=4√2/√2=4 c)=√(72)=6√2 d)=4√3+3√3=7√3    licze na naj 

Dodaj swoją odpowiedź