Na jutro.! . ;/ Przedstaw w prostszej postaci: a)(sin α + cos α)² - 2sin α cos α b)(tg α + ctg α)² - (th α - ctg α)² c)(cos α tg α)² - (sin α ctg α)² d) sin α cos α (tg α + ctg α)

a) (sinL+cosL)^{2}-2sinLcosL= sin^{2}L+2sinLcosL+cos^{2}L-2sinLcosL= sin^{2}L+cos^{2}L=1   b) (tgL+ctgL)^{2}-(tgL-ctgL)^{2}= tg^{2}L+2tgLctgL+ctg^{2}L-(tg^{2}-2tgLctgL+ctg^{2}L)= tg^{2}L+2tgLctgL+ctg^{2}L-tg^{2}L+2tgLctgL-ctg^{2}L= 2tgLctgL+2tgLctgL=4tgLctgL   c) (cosLtgL)^{2}-(sinLctgL)^{2} =(cosLcdotfrac{sinL}{cosL})^{2}-(sinLcdotfrac{cosL}{sinL})^{2}= sin^{2}L-cos^{2}L   d)sinLcosL(tgL+ctgL)=sinLcosL(frac{sinL}{cosL}cdotfrac{cosL}{sinL})=sinLcosL   W razie jakichkolwiek pytań śmiało pisz to odpowiem:)