a) a1 = 3 r = 2 n = 8 zatem an = a1 +( n -1)*r =3 + (n-1)*2 = 3 + 2 n - 2 = 2 n + 1 an = 2 n + 1 =========== a2 = 2*2 + 1 = 5 a3 = 2*3 + 1 = 7 a4 = 2*4 + 1 = 9 a5 = 2*5 + 1 = 11 a6 = 2*6 + 1 = 13 a7 = 2*7 + 1 = 15 a8 = 2*8 + 1 = 17 ===================== b) a1 = 3/5 r = 1/5 zatem an = a1 + (n -1)*r = 3/5 + (n -1)*(1/5) = 3/5 + (1/5) n - 1/5 = (1/5) n + 2/5 an = (1/5) n + 2/5 =================== zatem a6 = (1/5)*6 + 2/5 = 6/5 + 2/5 = 8/5 ====================================
1] a₁=3 r=2 n=8 a₈=a₁+7r a₈=3+7×2 a₈=17 ........... an=a₁+(n-1)r a₂=3+(2-1)×2=5 a₃=3+(3-1)×2=7 a₄=3+(4-1)×2=9 a₅=3+(5-1)×2=11 a₆=3+(6-1)×2=13 a₇=3+(7-1)×2=15 a₈=3+(8-1)×2=17 2] a₁=⅗ r=⅕ a₆=a₁+5r a₆=⅗+5×⅕ a₆=⅗+1 a⁶=1⅗
