Jaki musi byc stosunek masy wody o temp.20 stopni C do masy wody o temp. 0 stopni C

szukane: mw/ml =? t1= 20 st C= 293 K t2= 0 st C= 273 K ΔT= t1-t2 cw= 4190 J/kg K ct= 335 000 J/kg Qt= ct* ml Qw= mw* cw* ΔT ct*ml= mw* cw* ΔT ct/ (cw* ΔT)= mw/ ml mw/ ml= 335 000 J/kg / (4190 J/kg K* 293 K) mw/ml≈ 0, 27