a) (-x+1)(3-xdo kwadratu)-(xdo kwadratu +2)(x+3) podtzrebuje to na czwartek z góry dziekuje :)

(-x+1)(3-x²)-(x²+2)(x+3)=-3x+x³+3-x²-x³-3x²-2x-6=-4x²-5x-3

[latex][latex] (-x+1)(3-x^{2})-(x^{2} +2)(x+3)= -3x+x^{3}+3-x^{2}-(x^{3}+3x^{2}+2x+6)= -3x+x^{3}+3-x^{2}-x^{3}-3x^{2}-2x-6= -4x^{2}-5x-3[/latex][/latex]