Pole rombu P z przekątnych
f₁ = 5cm
f₂ = 6cm
[latex]P = frac{ f_{1} * f_{2} }{2} = frac{5cm * 6cm}{2} = frac{30 cm^{2} }{2} = 15 cm^{2} [/latex]
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2. Pola kwadratów P
dla kwadratu o boku a
a= 5cm
P = a² = (5cm)² = 25cm²
dla kwadratu o boku a
a = 6cm
P = a² = (6cm)² = 36cm²
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3)
[latex] frac{3}{5} * frac{6}{4} = frac{3 * 6}{5 * 4} = frac{18}{20} [/latex]
skrócimy ułamek
[latex] frac{18}{20} = frac{18 : 2}{20 : 2} = frac{9}{10} = 0,9[/latex]
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4)
[latex]5 frac{3}{5} + frac{6}{4} = 5 frac{3 * 2}{5 * 2} + 1 frac{2}{4} =5 frac{6}{10} + 1 frac{2 : 2}{4 :2} = 5 frac{6}{10} + 1 frac{1}{2} = 5 frac{6}{10} + 1 frac{1 * 5}{2 * 5} = 5 frac{6}{10} + 1 frac{5}{10} [/latex]
[latex]= 6 frac{11}{10} = 6 + 1 + frac{1}{10} = 7 frac{1}{10} [/latex]
zapis do zeszytu
6 3/5 + 6/4 = 5 6/10 + 1 2/4 = 6 6/10 + 1/2 = 6 6/10 + 5/10 = 6 11/10 = 7 1/10
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Pole równoległoboku P
a = 6cm ( bok równoległoboku)
h = 5cm (wysokość opuszczona na a)
P = ah = 6cm * 5cm = 30cm²
