oblicz pola powierzchni narysowanych ostrosłupów prawidłowych. Zdjecie w załączniku.

A) 10 *8=80 80 * 4 =320 8*5 = 40 320+40 = 360 cm ²

[latex]a) P_{p} = 8^{2}[/latex] [latex]P_{p} = 64[/latex] [latex]h^{2} = 10^{2} - 4^{2}[/latex] [latex]h^{2} = 100-16[/latex] [latex]h^{2} = 84[/latex] [latex]h = 2 sqrt{21} [/latex] [latex]P_{b} = frac{1}{2} * 8 * 2 sqrt{21} [/latex] [latex]P_{b} = 8 sqrt{21} [/latex] [latex]P_{c} = 64 + 4 * 8 sqrt{21} [/latex] [latex]P_{c} = 32(2 sqrt{21})[/latex] [latex]b) P_{p} = a^{2} sqrt{ frac{3}{4} } [/latex] [latex]P_{p} = 10^{2} sqrt{ frac{3}{4} } [/latex] [latex]P_{p} = 100 sqrt{ frac{3}{4} } [/latex] [latex]P_{p} = 25 sqrt{3} [/latex] [latex]h^{2} = 13^{2} - 5^{2}[/latex] [latex]h^{2} = 144 | sqrt{} [/latex] [latex]h=12[/latex] [latex]P_{b} = frac{1}{2} * 10 * 12[/latex] [latex]P_{b} = 60[/latex] [latex]P_{c} = 3*60+25 sqrt3} [/latex] [latex]P_{c} = 180+25 sqrt{3} [/latex] [latex]c) P_{p} = 6*a^{2} sqrt{ frac{3}{4} } [/latex] [latex]P_{p} = 6*4^{2} sqrt{ frac{3}{4} } [/latex] [latex]P_{p} = 24 sqrt{3} [/latex] [latex]h^{2} = 7^{2} - 2^{2}[/latex] [latex]h^{2} = 45[/latex] [latex]h=3 sqrt{5} [/latex] [latex]P_{b} = frac{1}{2} * 4 * 3 sqrt{5} [/latex] [latex]P_{b} = 6 sqrt{5} [/latex] [latex]P_{c} = 23 sqrt{3} + 6 * 6 sqrt{5} [/latex] [latex]P_{c} = 6(4 sqrt{3} + 6 sqrt{5} )[/latex]