Oblicz ile Newtonow dziala na cm2 tloka o srednicy 80mm jezeli w cylidrze panuje cisnienie 10mPa

d = 80 mm r = d/2 r = 40 mm = 0,04 m                bo 1 m = 1000 mm p = 10 mPa = 0, 01 Pa = 0,01 N/m²               bo 1 mPa = 0,001 Pa S = πr^2 [latex]p = frac{F}{S } /* S [/latex] [latex]F = p * S [/latex] [latex]F = p * pi r^2[/latex] [latex]F = 0,01 frac{N}{m^2 } * 3,14 * ( 0,04 m )^2 = 0,00005024 N = 5,024 *10 ^{-5} N[/latex]

[latex]dane:\d = 80 mm = 0,08 m\r = frac{d}{2} = 0,04 m=4 cm\p = 10 mPa = 10cdot0,001Pa = 0,01 Pa = 0,01frac{N}{m^{2}}\pi = 3,14\\szukane:\F = ?[/latex] [latex] p = frac{F}{S} |cdot S\\F = pcdot S[/latex] [latex]p = 0,01frac{N}{m^{2}} = 0,01cdotfrac{N}{10000cm^{2}} = 0,000001frac{N}{cm^{2}}=10^{-6} frac{N}{cm^{2}}\\S = pi r^{2} = 3,14cdot (4cm)^{2} = 50,24 cm^{2}=5,024cdot10 cm^{2}[/latex] [latex]F = 10^{-6}frac{N}{cm^{2}}cdot5,024cdot10cm^{2}\\F = 5,024cdot10^{-5} N[/latex]