2pierwiastki z trzech do potęgi 3 ile to jest?

[latex](2sqrt3)^3=2^3*sqrt3^3=\\=8sqrt{27}=8sqrt{9*3}=\\=8*3sqrt3=24sqrt3[/latex]

[latex](2sqrt{3})^{3} = 2^{3}cdot(sqrt{3})^{3} = 8cdot(sqrt{3})^{2}cdotsqrt{3} = 8cdot3cdotsqrt{3} = 24sqrt{3}[/latex]