Ktoś coś ? byłbym wdzięczny w(x)=4x3-8x2-x+2= w(x)=4x3-4x2-9x+9= w(x)=x4-x3-8x2+8x=

[latex]4x^3-8x^2-x+2=4x^2(x-2)-(x-2)=(x-2)(4x^2-1)= \ (x-2)(2x-1)(2x+1) \ 4x^3-4x^2-9x+9=4x^2(x-1)-9(x-1)=(x-1)(4x^2-9)= \ (x-1)(2x-3)(2x+3) \ x^4-x^3-8x^2+8x=x^3(x-1)-8x(x-1)=(x-1)(x^3-8x)= \ (x-1)x(x^2-8)=x(x-1)(x- sqrt{8} )(x+ sqrt8} )[/latex]

[latex]4x^3-8x^2-x+2=4x^2(x-2)-(x-2)=(x-2)(4x^2-1)=(x-2)(2x-1)(2x+1)[/latex] [latex]4x^3-4x^2-9x+9=4x^2(x-1)-9(x-1)=(x-1)(4x^2-9)=(x-1)(2x-3)(2x+3)[/latex] [latex]x^4-x^3-8x^2+8x=x^3(x-1)-8x(x-1)=(x-1)(x^3-8x)=(x-1)x(x^2-8)=x(x-1)(x- sqrt{8})(x+ sqrt{8})[/latex]