8 * x do potęgi 3 = -1 ile wynosi x ????  pomocyyyy na jutro !!!!!!!!! dam naj

8* x³ = -1 x³ = -1/8 x³ = (-1/2)³ x=-1/2

[latex]8cdot x^{3} = -1 /:8\\x^{3} = -frac{1}{8}\\x^{3} = (-frac{1}{2})^{3}\\x = -frac{1}{2}[/latex]