0,3z+5=0,5z+0,6 0.3z - 0.5z = 0.6 - 5 |*10 3z - 5z = 6 - 50 | (-1) -3z + 5z = -6 + 50 2z = 44 |:2 z = 22 3(2x+1)=10x-0,6 6x + 3 = 10x - 0.6 6x - 10x = -0.6 - 3 |*(-1) -6x + 10x = 0.6 + 3 4x = 3.6 |:4 x = 0.9 0,2(1-0,3x)=0,04x+1 0.2 - 0.06x = 0.04x + 1 |*100 20 - 6x = 4x + 100 -6x -4x = 100 - 20 -10x = 80 |: (-10) x = -8 -2,5(0,4x-0,1)=4(1+0,5x) -x + 2.5 = 4 + 2x -x - 2x = 4 - 2.5 -3x = 1.5 |:(-3) x = -0.5 x/2+x/2+3=4 |*2 x + x + 6 = 8 2x = 8 - 6 2x = 2 |:2 x = 1 1/2x+1/2x-5=1 |*2 x + x - 10 = 3 2x = 3 + 10 2x = 13 |: 2 x = 6.5 y/2-y/4-1=2 |*4 2y - y - 4 = 8 y = 8 + 4 y = 12 1/2y+1/3y-2=3 |*6 3y + 2y - 12 = 18 5y = 18 + 12 5y = 30 |:5 y = 6 2z/3-3z/4-1/6=1 |*12 8z - 9z - 2 = 12 -z = 12 + 2 -z = 14 |*(-1) z = -14 z-5z/6=4-z/3 |*6 z - 5z = 8 - 2z z - 5z + 2z = 8 -2z = 8 |:(-2) z = -4 y/2+7/5y-5/2=1,3 |*10 5y + 14y - 25 = 13 19y = 13 + 25 19y = 38 |: 19 y = 2
1/ 0,3z+5=0,5+0,6 5-0,6=0,5z-0,3z 4,4=0,2z z=22 2/ 3(2x+1)=10x-0,6 6x+3=10x-0,6 3+0,6=10x-6x 3,6=4x x=3,6/4 x=0,9 3/ 0,2(1-0,3x)=0,04x+1 0,2-0,6x=0,04x+1 0,2-1=0,04x+0,6x -0,8=0,64x x=-0,8/0,64 4/ -2,5(0,4x-0,1)=4(1+0,5x) 0,6x+0,25=4+2x 0,6x-2x=4-0,25 -1,4x=3,75 x=2,25 5/ x/2+x/2+3=4 0,5x+0,5x+3=4 1x+3=4 x=4-3 x=1 6/ 1/2x+1/2x-5=1 x0,5x+0,5x-5=1 x-5=1 x=1+5 x=6 7/ y/2-y/4-1=2 0,5y-0,25y-1=2 0,75y-1=2 0,75y=2+1 0,75y=3 y=1,5 8/ 1/2y+1/3y-2=3 (te liczby które podam w nawiasach zamiast ukośnika zpisuj w ułamku zwykłym) (1/2y)+(1/3y)-2=3 (3/6y)+(2/6y)-2=3 (5/6y)-2=6 (5/6y)=3+2 (5/6y)=5 y=5(5/6) 9/ 2z/3-3z/4-1/6=1 (te liczby które podam w nawiasach zamiast ukośnika zpisuj w ułamku zwykłym) (2/6z)-(3/4z)-(1/6)=1 (1/3z)-(3/4z)-(1/6)=1 (4/12z)-(9/12)z-(1/6)=1 1(1/12z)-(1/6)=1 1(1/12z)=1(1/6) 10/ z-5z/6=4-z/3 z-(5/6z)=54-)(1/3z) 1(5/6z)+(1/3z)=4 1(5/6z)+(2/6z)=4 2(1/6z)=4 z=4/2(1/6) 11/ y/2+7/5y-5/2=1,3 0,5y+1,4y-2,5=1,3 1,9y-2,5=1,3 1,9y=1,3+2,5 1,9y=3,7 y=3,7/1,9 To wszystko co wiem z góry przepraszam za błędy :) Chociaż nie powinno ich być :P
