Liczba [latex]3*sqrt{3sqrt{3}}[/latex] jest równa: [latex]3^{1,75}[/latex] Proszę o wyjaśnienie sposobu rozwiązania tego zadania.

[latex]3*sqrt{3*3^{1/2}} = 3*(3*3^{1/2})^{1/2} = 3*(3^{1,5})^{0,5}=3*3^{0,75}=3^{1+0,75}=3^{1,75}[/latex]

3* p [3 *p(3)] = 3* p[ 3* 3^(1/2)] = 3*p [ 3 ^(1 + 1/2)] = 3* p [ 3^(3/2)] = = 3* [ 3 ^ (3/2) ] ^(1/2) = 3* 3^( (3/2)*(1/2)) = 3* 3 ^(3/4) = 3 ^( 1+ 3/4) = = 3^ (7/4)  = 3 ^ 1,75 ====================