zad 1 1 1/6 + 3 1/5 : 3 11/15= =7/6 + 16/5 : 56/15= =7/6 + 16/5 * 15/56= =7/6 + 2 * 3/7= =7/6 + 6/7= =49/42 + 36/42= =85/42= =2 1/42 ============ zad 2 a⁴*(a¹²:a⁴)= =a⁴*a¹²⁻⁴= =a⁴*a⁸= =a⁴⁺⁸=a¹² ============ zad 3 czy miało być "3 1/3 i-2,5"? (3 1/3 -2,5)²= =(10/3 - 25/10)²= =(100/30 - 250/30)²= =(50/30)²=(5/3)²=25/9
[latex]1frac{1}{6}+3frac{1}{5}:3frac{11}{15} =1frac{1}{6}+frac{16}{5}:frac{56}{15}=1frac{1}{6}+frac{16}{5}*frac{15}{56}=1frac{1}{6}+frac{6}{7}=1frac{7}{42}+frac{36}{42}=1frac{43}{42}[/latex][latex]=2frac{1}{42}[/latex] [latex] a ^{4} * ( a^{12} : a ^{4} ) =a^{4}*a^{8}=a^{12}[/latex] [latex][3frac{1}{3}+( -2,5)]^{2}=(3frac{1}{3}-2frac{1}{2})^{2}=(3frac{2}{6}-2frac{3}{6})^{2}=(frac{5}{6})^{2}=frac{25}{36}[/latex]
