a) Rozwiąż równanie x kwadrat + 4x - 5 =0 B) rozwiąz nierówność x kwadrat +2x - 3 >0

a) [latex]x^{4}+4x-5=0[/latex] [latex]delta=b^{2}-4ac[/latex]   [latex]delta=4^{2}-(4cdot1cdot(-5)) [/latex]   [latex]delta=16+20=36[/latex]   [latex]sqrt{delta}=sqrt{36}=6[/latex]   [latex]x_{1}=frac{-b-sqrt{delta}}{2a} [/latex]   [latex]x_{1}=frac{-6-4}{2}=-5[/latex]   [latex]x_{2}=frac{-b+sqrt delta}{2a} [/latex]    [latex]x_{2}=frac{-4+6}{2}=1[/latex]   b) [latex]x^{2}+2x-3>0[/latex]   [latex]delta=2^{2}-(4cdot1cdot(-3))[/latex]   [latex]delta=4+12=16[/latex]   [latex]sqrt{delta}=sqrt{16}=4[/latex]   [latex]x_{1}=frac{-4-6}{2}=-3[/latex]   [latex]x_{2}=frac{-2+4}{2}=1[/latex]