Zad.11,str.47,P-MATEMATYKA WOKÓŁ NAS 2 GIMNAZJUM Oblicz:a)[latex] sqrt{1 frac{7}{9} } [/latex] b)[latex] sqrt{1,21} [/latex] c)([latex] sqrt[]{3} [/latex]) do drugiej d)([latex] sqrt[2]{5} [/latex]) do trzeciej e)[latex] sq

√(1 7/9) =√(16/9) =4/3 √1,21 =√(121/100) =11/10 =1 1/10 (√3)² =√3*√3 =3 (√5)³ =5√5 ∛(3 3/8) =∛(27/8) =3/2 =1 1/2 ∛(-64/125) =-4/5

[latex]a). sqrt{1 frac{7}{9} } = sqrt{ frac{16}{9} } = frac{ sqrt{16} }{ sqrt{9} } = frac{4}{3} =1 frac{1}{3} \ \ b). sqrt{1,21} = sqrt{1 frac{21}{100} } = sqrt{ frac{121}{100} } = frac{ sqrt{121} }{ sqrt{100} } = frac{11}{10} =1 frac{1}{10} \ \ c).( sqrt{3} ) ^{2} = sqrt{9} =3 \ \ d).( sqrt[2]{5} ) ^{3} = sqrt{5 } ^{3} = sqrt{125} = sqrt{25*5} =5 sqrt{5} [/latex] [latex]e). sqrt[3]{3 frac{3}{8} } = sqrt[3]{ frac{27}{8} } = frac{ sqrt[3]{37} }{ sqrt[3]{8} } = frac{3}{2} =1 frac{1}{2} \ \ f). sqrt[3]{- frac{64}{125} } =- sqrt[3]{ frac{64}{125} } =- frac{ sqrt[3]{64} }{ sqrt[3]{125} } =- frac{4}{5} [/latex]