[latex]l = 2 m \ d = 0,02 mm = 2 cdot 10^{-5} m \ ho = 1,7 cdot 10^{-8} Omega cdot m \ \ R = ho frac{l}{S} = ho frac{l}{pi r^2} = ho frac{l}{pi (frac{d}{2})^2} = frac{4 ho l}{pi d^2} \ R = frac{4 cdot 1,7 cdot 10^{-8} cdot 2}{pi cdot (2 cdot 10^{-5})^2} = 108 Omega[/latex] Odp.: Opór wynosi 108 Omów.
dane: l = 2 m d = 0,02 mm r = d/2 = 0,01 mm = 1 *10^-5 m p(ro) = 1,7 *10^-8 om*m szukane: R = ? R = p *l/S S = TTr^2 = 3,14 *(10^-5m)^2 = 3,14 *10^-10 m2 R = 1,7 *10^-8 om*m * 2m/(3,14 ^10^-10m2) = 1,0828 *10^2 om = 108,28 oma R = 108,3 oma =============
