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/ - pierwiastek A (6+/5)^2=36+12/5+5+41+12/5 B (/11-3)(/11+3) =11-9=2 C (/7-/13)^2=7-2/91+13=20-2/91 D (x+12)^2= x^2+24x+144 E (3x-4)(3x+4)=3x^2-16 F (8-5x)^2=64-80x+25x^2

a) [latex] (6+ sqrt{5})^{2} = 36+12 sqrt{5} + 5= 41+12 sqrt{5} [/latex] b) [latex]( sqrt{11} -3)( sqrt{11} +3)= 11-9=2[/latex] c) [latex]( sqrt{7} - sqrt{13})^{3} = 7 sqrt{7} - 21 sqrt{13} + 39 sqrt{7} -13 sqrt{13} =46 sqrt{7} - 34 sqrt{13} [/latex] d)[latex](x+12)^{2} = x^{2} +24x+144 [/latex] e)[latex](3x-4)(3x+4)=9x^{2} - 16[/latex] f) [latex](8-5x)^{2} = 64-80x+25 x^{2} [/latex]