a x^3 + 2x^2 - 16x -32 = 0 b -12x^3+x^2+x=0 Rozwiąż Równanie !!!!! Pliss POMOCY !!!!!!!!!!!!!!!!!!!!!!!!!

[latex]x^3 + 2x^2 - 16x -32 = 0\\x^2(x+2)-16(x+2)=0\\(x^2-16)(x+2)=0\\(x-4)(x+4)(x+2)=0[/latex]   x - 4 = 0   v   x + 4 = 0   v    x+2=0 x = 4   v    x = -4   v   x = -2   Z={-4,-2,4}   [latex]-12x^3+x^2+x=0 /*(-1)\\12x^3-x^2-x=0\\x(12x^2-x-1)=0[/latex]   x = 0   v   12x² - x - 1= 0                 Δ = 1-4*12*(-1) = 1 + 48 = 49                 x₁=(1 + 7)/24 = 8/24=1/3                 x₂ = (1 - 7)/24 = -6/24 = -1/4 [latex]Z={-frac{1}{4}, 0, frac{1}{3}}[/latex]