Liczba x=[latex]frac{sqrt[]{10} plus sqrt[]{2}}{sqrt[]{5} plus 1}[/latex] jest równa   a) [latex]sqrt{2}[/latex] b) [latex]sqrt{5}[/latex] c) 2[latex]sqrt{2}[/latex] d) 2    

[latex]x=frac{sqrt{10}+sqrt{2}}{sqr{5}+1}=frac{(sqrt{10}+sqrt{2})(sqr{5}-1)}{(sqr{5}+1)(sqr{5}-1)}=[/latex] [latex]=frac{sqrt{50}+sqrt{10}-sqrt{10}-sqrt{2}}{5-1}=frac{5sqrt{2}-sqrt{2}}{4}=sqrt{2}[/latex] Odp. a) Pozdr: i liczę na naj:)