Proszę o szybką opowiedz Zadanie 1 Do 5kg 5% roztworu cukru dodano 100g cukru. Jakie jest stężenie procentowe otrzymanego roztworu? Zadanie 2 Z 200g 5% roztworu odparowano 75g wody. Oblicz stężenie procentowe powstałego roztworu. Zadanie 3 Obl

zad.1 mr₁ = 5kg = 5000g Cp₁ = 5% Cp = ms/mr * 100% ==> ms = Cp*mr/100% ms₁ = 5%*5000g/100% = 250g ms₂ = 250g + 100g = 350g mr₂ = 5000g + 100g = 5100g Cp₂ =? Cp₂ = 350g/5100g * 100% = 6,86% zad.2 mr₁ = 200g Cp₁ = 5% Cp = ms/mr * 100% ==> ms = Cp*mr/100% ms₁ = 5%*200g/100% = 10g ms₂ = ms₁ = 10g mr₂ = 200g - 75g = 125g Cp₂ = ? Cp₂ = 10g/125g * 100% = 8% zad.3 ms = 250g V(H₂O) = 1l = 1dm³ = 1000cm³ d(H₂O) = 1g/cm³ d = m/V ==> m=d*V m(H₂O) = 1000cm³*1g/cm³ = 1000g mr = m(H₂O) + ms = 1000g + 250g = 1250g Cp = ms/mr * 100% = 250g/1250g * 100% = 20%

1) 5kg-100% x-5% (5*5):100= 0,25 kg =250g 250+100 =350g 5kg +100 = 5100 g 5100-100% 350-x% =6,8 2) 200 g-100% x-5% =10g 200g -75g=125g 125g-100% 10-x =8% 3) 1l=1kg=1000g 1000+250=1250g 1250g=100% 250-x =20