Oblibcz   a) [(3 1/2)^-1 - 14^-1]^-2 b) [(2 1/2)^-2 - (1 9/16)^-1]^-1 c) (0,1^-2 - 0,25^-1)^-1 d) [0,2^-1+(0,3)^-1]^-2   Bardzo bym prosiła o to żeby nie pisać samego wyniku bo nie wiem jakto zrobić a chciałabym wiedzieć jak to zrobiliście 

a) [(3 1/2)^-1-14^-1]^-2= =[(7/2)^-1-14^-1]^-2= =[(2/7)^-1-(1/14)^-1]^-2= =(2/7-1/14)^-2= =(4/14-1/14)^-2= =(3/14)^-2= =(14/3)^2= =196/9= =21 7/9   b) [(2 1/2)^-2 - (1 9/16)^-1]^-1 =[(5/2)^-2-(25/16)^-1]^-1= =[(2/5)^2-(16/25)^1)^-1= =(4/25-16/25)^-1= =(-12/25)^-1= =(-25/12)^1= =-25/12= =-2 1/12 c) (0,1^-2 - 0,25^-1)^-1= =[(1/10)^-2-(1/4)^-1]^-1= =(10^2-4^1)^-1= =(100-4)^-1= =96^-1= =(1/96)^1= =1/96    d) [0,2^-1+(0,3)^-1]^-2= =[)1/5)^-1+(3/10)^-1]^-2= =[5^1+(10/3)^1]^-2= =(5+10/3)^-2= =(15/3+10/3)^-2= =(25/3)^-2= =9/625= =0,0144