Bardzo proszę o szybką pomoc :/ Daję naj :) Reakcje zobojętniania: Wodorotlenek + kwas w. Baru (II) + kw. solny = II = II = II + kw. siarkowy (VI) = II = II = II + kw. azotowy (V) = II = II = II + kw. chlorowy (VII) = II = II = II + kw. bromowodor

Ba(OH)2+2HCl--->BaCl2+2H2O Ba2+ +2OH- +2H+ +2Cl- --->Ba2+ +2Cl- +2H2O 2OH- +2H+ --->2H2O Ba(OH)2+H2SO4-->BaSO4+2H2O Ba2+ +2OH- +2H+ +SO4 2- --->Ba2+ +SO4 2- +2H2O 2OH- +2H+ --->2H2O Ba(OH)2+2HNO3--->Ba(NO3)2+2H2O Ba2+ +2OH- +2H+ +2NO3- --->Ba2+ +2NO3- +2H2O 2OH- +2H+ --->2H2O Ba(OH)2+2HClO4--->Ba(ClO4)2+2H2O Ba2+ +2OH- +2H+ +2ClO4- --->Ba2+ +2ClO4- +2H2O 2OH- +2H+ --->2H2O Ba(OH)2+2HBr--->BaBr2+2H2O Ba2+ +2OH- +2H+ +2Br- --->Ba2+ +2Br- +2H2O 2OH- +2H+ --->2H2O Ca(OH)2+2HBr--->CaBr2+2H2O Ca2+ +2OH- +2H+ +2Br- --->Ca2+ +2Br- +2H2O 2OH- +2H+ --->2H2O MBaCl2=137 g/mol+2*35,5 g/mol=208 g/mol MBaSO4=137 g/mol+32 g/mol+4*16 g/mol=233 g/mol MBa(NO3)2=137 g/mol+2*14 g/mol+6*16 g/mol=261 g/mol MBa(ClO4)2=137 g/mol+2*35,5 g/mol+8*16 g/mol=336 g/mol MBaBr2=137 g/mol+2*80 g/mol=297 g/mol MCaBr2=40 g/mol+2*80 g/mol=200 g/mol

Ba(OH)2 + 2HCl ------> BaCl2 + 2H2O                   251 g/mol b)Ba(OH )2+ H2SO4 --------> BaSO4 + 2H2O        176 c) Ba(OH)2 + HNO3 ------> Ba(NO3)2 + 2H2O Ba(OH)2+ 2HClO4--->Ba(ClO4)2 + 2 H2O Ba(OH)2 + 2HBr------> BaBr2 + 2H2O Ba(OH)₂+2HBr ---> BaBr₂ + 2H₂O