Rozwiąz równania ; A) (x - 1 ) ² +2(x- 3) ² = 18x -10x B) (2x+ 5)² -(2x -5)² =3x²+ 41x-4

a) (x-1)²+2(x-3)² = 18x-10x x²-2x+1+2(x²-6x+9) = 8x x²-2x+1+2x²-12x+18-8x = 0 3x²-22x+19 = 0 a = 3,  b = -22,  c = 19 Δ = b²-4ac = 484-228 = 256 √Δ = 16  x1 = (-b-√Δ)/2a = (22-16)/6 = 6/6 = 1 x2 = (-b+√Δ)/2a = (22+16)/6 = 38/6 = 6⅓ Odp. x = 1    v    x = 6⅓   b) (2x+5)²-(2x-5)² = 3x²+41x-4 4x²+20x+25-(4x²-20x+25) = 3x²+41-4 4x²+20x+25-4x²+20x-25 = 3x²+41x-4 -3x²+40x-41x+4 = 0   -3x²-x+4 = 0   I*(-1) 3x²+x-4 = 0 a = 3,  b = 1,  c = -4 Δ = b²-4ac = 1+48 = 49 √Δ = 7  x1 = (-b-√Δ)/2a = (-1-7)/6 = -8/6 = -1⅓ x2 = (-b+√Δ)/2a = (-1+7)/6 = 6/6 = 1 Odp. x = -1⅓    v    x = 1