Proszę bardzo o zrobienie zadań 3 i 6 Jeśli nie dwa to chociaż jedno Bardzo ważne. daje naj

sqrt - pierwiastek z tego co jest w nawiasie 3 a) [latex]sqrt{4,25}: sqrt{1frac{19}{49}}+sqrt{11frac{1}{3}} :sqrt{4frac{2}{25}}= sqrt{frac{425}{100}}: sqrt{frac{68}{49}}+sqrt{frac{34}{3}} :sqrt{frac{102}{25}}= sqrt{frac{17*25}{100}}: sqrt{frac{4*17}{49}}+sqrt{frac{34}{3}*frac{25}{102}}= sqrt{frac{17*25}{100}*frac{49}{4*17}}+sqrt{frac{34}{3}*frac{25}{34*3})}= frac{5*7}{10*2}+frac{5}{3}=frac{7}{4}+frac{5}{3}=frac{41}{12}=3frac{5}{12}[/latex] b) [latex]sqrt[3](540):sqrt[3](20)-sqrt{1000}*sqrt{0,289}= sqrt[3]{frac{540}{20}}-sqrt{frac{1000*289}{1000}}= sqrt[3](27)-sqrt{17*17}=3-17=-14[/latex]  c) [latex]sqrt{19frac{3}{5}:sqrt{0,064:sqrt{0,16}}}*sqrt[3]{20frac{1}{4}:sqrt[3]{108:sqrt[3]{0,125}}}= sqrt{19frac{3}{5}:sqrt{frac{0,064}{0,4}}}*sqrt[3]{20frac{1}{4}:sqrt[3]{frac{108}{0,5}}}= sqrt{19frac{3}{5}:sqrt{0,16}}*sqrt[3]{20frac{1}{4}:sqrt[3]{216}}= sqrt{frac{98}{5}:0,4}*sqrt[3]{frac{81}{4}:6}=sqrt{49}*sqrt[3]{frac{81}{24}}= 7*sqrt[3]{frac{27}{8}}=7*frac{3}{2}=10frac{1}{2} [/latex] Za chwilę dopiszę resztę 6 a  [latex](sqrt{12}-10sqrt{27}-sqrt{75})*sqrt{frac{1}{3}}= (sqrt{3*4}-10sqrt{9*3}-sqrt{3*25})*sqrt{frac{1}{3}}= (2sqrt{3}-30sqrt{3}-5sqrt{3})*sqrt{frac{1}{3}}= -33sqrt{3}*sqrt{frac{1}{3}}=-33[/latex] b [latex](4sqrt[3]{16}-5sqrt[3]{54}-3sqrt[3]{128}):sqrt[3]{2}= (4sqrt[3]{8*2}-5sqrt[3]{2*27}-3sqrt[3]{2*64}):sqrt[3]{2}= (8sqrt[3]{2}-15sqrt[3]{2}-12sqrt[3]{2}):sqrt[3]{2}= -19sqrt[3]{2}:sqrt[3]{2}=-19[/latex]  c [latex](5sqrt{0,54}-sqrt{0,06}+5sqrt{0,24}):sqrt{6}= (5sqrt{6*0,09}-sqrt{6*0,01}+5sqrt{6*0,04}):sqrt{6}= (1,5sqrt{6}-0,1sqrt{6}+sqrt{6}):sqrt{6}= 2,4sqrt{6}:sqrt{6}=2,4[/latex]