Witaj ;) Dane: Szukane: mr1 = 50 g ms = ? Cp1 = 4% Cp2 = ? ms+ = 10 g ms2 = ? mr2 = ? Rozwiązanie: ms = (Cp1*mr1)/100% ms = (4%*50g)/100% ms = 2 g - tyle mamy siarkowodoru w roztworze przed dodaniem kolejnych 10 g siakowodoru ms2 = ms + ms+ ms2 = 2 g + 10 g ms2 = 12 g mr2 = mr1 + ms+ mr2 = 50 g + 10 g mr2 = 60 g Cp2 = (ms2/mr2)*100% Cp2 = (12 g/60 g)*100% Cp2 = 20 % Odp: Stężenie procetnowe otrzymanego roztworu wynosi 20%. Zad.2. Dane: Szukane: mr1 = 120 g ms = ? Cp1 = 5% mr2 = ? mrozp+ = 80 g Cp2 = ? Rozwiązanie: ms = (120 g* 5%)/100% ms = 6 g mr2 = mr1 + mrozp+ mr2 = 120 g + 80 g mr2 = 200 g Cp2 = (ms/mr)*100% Cp2 = (6 g/200 g)*100% Cp2 = 3% Odp: Stężenie procentowe otrzymanego roztworu wynosi 3%.
1)Cp=4% mr=50g ms=Cp*mr/100% ms=4*50/100 ms=2g Po DODANIU 10g H₂S ms=10g+2g=12g mr=10g+50g=60g Cp=ms*100%/mr Cp=12*100/60 Cp = 20% 2)Cp=5% mr=120g ms=Cp*mr/100% ms=5*120/100 ms=6g Po DODANIU 80g wody ms=6g mr=80g+120g=200g Cp=ms*100%/mr Cp=6*100/200 Cp = 3%