oblicz pracę jaką wykona dźwig o mocy 9Kw pracujoncy przez 5min

P = 9kW = 9000W t = 5min = 300s   P = W/t => W = Pt W = 9000W x 300s = 27 x 10⁵J       ---------------------------------------------------------------------------------------------------- Litterarum radices amarae sunt, fructus iucundiores   Pozdrawiam :)

[latex]\\ P=9kW=9000W bo 1kW=1000W \\ t=5min=5 cdot 60s=300s \\ P=frac{W}{t}| cdot t \\ W=P cdot t \\ W=9000W cdot 300s \\ W=2700000J\\ W=2,7MJ[/latex]