C7H16 H H H H H H H | | | | | | | H-C-C-C-C-C-C-C-H | | | | | | | H H H H H H H CH3 - (CH2)5 - CH3 2. C45H92 3. C8H18 4. Butan C4H10 100 % - 12 * 4 + 10 * 1 = 58 x % - 10 10* 100 / 58 = 17,2%
Witaj ;) Zad. 1. Wzór ogólny: [latex]C_{n}H_{2n+2}[/latex] [latex]C_{7}H_{16}[/latex] - heptan [latex]CH_{3}-CH_{2}-CH_{2}-CH_{2}-CH_{2}-CH_{2}-CH_{3}[/latex] Wzór strukturalny w załączniku ;) Zad. 2. [latex]C_{n}H_{2n+2}[/latex] 2n+2 = 92 2n = 92-2 2n = 90/2 n = 45 [latex]C_{45}H_{92}[/latex] Zad. 3. 12 n + 2n+2 = 114 14 n + 2 = 114 14 n = 114 - 2 14 n = 112/14 n = 8 [latex]C_{8}H_{18}[/latex] - oktan Zad. 4. [latex]m_{C_{4}H_{10}}=4*12u+10*1u=58u[/latex] %H = (10 u/58 u)*100% %H = 17,24% Odp: Zawartość procentowa wodoru w butanie wynosi 17,24%.