Rozwiąż równania  a) 3x^{2} + 10x +3=0 \ b) -x^{2} + 3 x + 4 = 0\ c)25x^{2} - 10x + 1 =0[/tex] 

a) 3x^{2} + 10x +3=0 Δ = 10² - 4 *  3 * 3 = 100 - 36 = 64 √Δ = 8 x1 = (10 - 8) / 6 = 2/6 = 1/3 x2 = (10 + 8)/6 = 18/6 = 3 b) -x^{2} + 3 x + 4 = 0 x^2 - 3x - 4 = 0 Δ = (-3)² - 4 *  1 * (-4) = 9 + 16 = 25 √Δ = 5 x1 = (3 - 5) / 2 = - 2/2 = -1 x2 = (3 + 5)/2 = 8/2 = 4   c) 25x^{2} - 10x + 1 =0 Δ = (-10)² - 4 *  25 * 1 = 100 - 100 = 0 x0 = -b/2a = 10/50 = 1/5