- x^2 + 5 x + 3 = 0 ----------------------- delta = b^2 - 4ac = 5^2 - 4*(-1)*3 = 25 + 12 = 37 p(delty) = p(37) x = [ - 5 - p(37)]/ ( - 2) = 2,5 + 0,5 p(37 ) lub x = [ - 5 + p(37)]/ ( -2) = 2,5 - 0,5 p(37) =========================================== 4 x^2 - 12 x + 1 = 0 --------------------------- delta = ( -12)^2 - 4*4*1 = 144 - 16 = 128 = 64*2 p( delty) = 8 p(2) x = [ 12 - 8 p(2)] / 8 = 1,5 - p(2) lub x = [ 12 + 8 p(2)] /8 = 1,5 + p(2) =================================== - 4 x^2 + 9 x - 9 = 0 ------------------------ delta = 9^2 - 4*(-4)*(-9) = 81 - 144 < 0 Równanie nie ma pierwiastków. ================================ gdzie p(37) - pierwiastek kwadratowy z 37 p(2) - pierwiastek kwadratowy z 2
