oblicz masy cząsteczkowe podanych związków chemicznych mCuO= mFe2O3= mNa2CO3= mH2SO4 mCa(oh20) mFe2(SO3)3=

mCuO=64u+16u=80u mFe2O3=2*56u+3*16u=160u mNa2CO3= 2*23u+12u+3*16u = 106u mH2SO4= 2*1u+32u+4*16 = 98u mCa(OH)2= 40u+2*16u+2*1u = 74u mFe2(SO3)3=2*56u+(32u+3*16u)3 = 352u

u - unit mCuO = 1*64u + 1*16u = 80u  mFe2O3 = 2*56u + 3*16u = 112u + 48u = 160u mNa2CO3 = 2*23u + 3*59u = 46u + 177u = 223u mH2SO4 = 2*1u + 1*32u + 4* 16u = 2u + 23u + 64u = 89u mCa(OH)2 = 1*40u + 2*16 + 2*1 = 40u + 32u + 2u = 74u mFe2(SO3)3 = 2*56u + 3*32u + 9*16u = 112u +96u + 144u = 352u