1.wyznacz ile energii potrzeba, aby zmienic 10 kg lodu o temp -15st C w wode o temp 20 st. C 2.oblicz energie potrzebna do zamiany 10 kg lodu o temp -10 st. C w wode o temp 100 st. C  

zad.1 Q = m *cw *ΔT Q₁ = 10 kg * 2100 J/kg * C * ( 0 C - (-15 C ) Q₁ = 315000 J = 315 kJ Q₂ = m * ck Q₂ = 10 kg *334000 J/kg Q₂ = 3340000 J = 3340 kJ Q₃ = m *cw *ΔT Q₃ = 10 kg *4200 J/kg * C * ( 20 C - 0 C ) Q₃ = 840000 J = 840 kJ Q = Q₁ + Q₂ + Q₃ Q = 4495 kJ zad.2. Q = m *cw *ΔT Q₁ = 10 kg * 2100 J/kg * C * ( 0 C - (-10 C ) Q₁ = 210000 J = 210 kJ Q₂ = m * ck Q₂ = 10 kg *334000 J/kg Q₂ = 3340000 J = 3340 kJ Q₃ = m *cw *ΔT Q₃ = 10 kg *4200 J/kg * C * ( 100 C - 0 C ) Q₃ = 4200000 J = 4200kJ Q = Q₁ + Q₂ + Q₃ Q = 7750 kJ