1. a = 10cm b = 13cm (1/2a)^2 + h^2 = b^2 5^2 + h^2 = 13^2 h^2 = 169 - 25 h^2 = 144 h = 12cm ----------- wysokość trójkąta P = 1/2 * a * h = 1/2 * 10 * 12 = 60cm^2 r = 2P / (a + b + c) --------- wzór na promien koła wpisanego w trójkąt r = (2 * 60) / (10 + 13 + 13) r = 120 / 36 r = 20/6 r = 10/3 cm P = π r² P = π * (10/3)² P = 100/9 π P = 11 i 1/9 π cm² ----------- odpowiedź 2. d1 = 6cm d2 = 8cm (1/2d1)^2 + (1/2d2)^2 = a^2 a^2 = 3^2 + 4^2 a^2 = 9 + 16 a^2 = 25 a = 5cm ---------- bok rombu P = 1/2 * d1 * d2 = 1/2 * 6 * 8 = 24cm^2 ---------- pole rombu r = 2P / (a + a + a + a) r = (2 * 24) / (4 * 5) r = 48/20 r = 24/10 r = 2,4cm P = π r² P = π * 2,4² P = 5,76 π cm² ----------- odpowiedź
