doprowadz wyrazenie do najprostrzej postaci; √75-√27+√12= (2√2+3)²= (1+√7)(1-√7)= √72+√32-√8= (3√3-2)²= (2+√5)(2-√5)=   oblicz: 5×(2½)⁻¹= √5 i 9/27÷√1 i 3/9= ∛4×∛250-√7×√63= (1⅓)⁻¹÷2= (√54÷√3)÷√2= √15×√⅗+∛20×∛⅖=

√75-√27+√12 = √(25·3)-√(9·3)+√(4·3) = √25√3-√9·√3+√4·√3 = 5√3-3√3+2√3 = 4√3 (2√2+3)² = (2√2)²+2·2√2·3+3² = 8+12√2+9 = 17+12√2 (1+√7)(1-√7) = 1²-(√7)² = 1-7 = -6 √72+√32-√8 = √(36·2)+√(16·2)-√(4·2) = 6√2+4√2-2√2 = 8√2  (3√3-2)² = (3√3)²-2·3√3·2+2² = 27-12√3+4 = 31-12√3 (2+√5)(2-√5) = 2²-(√5)² = 4-5 = -1   5·(2½)⁻¹ = 5·(5/2)⁻¹ = 5·(2/5) = 2 ⁹/₂₇√5 : ³/₉√1 = ⅓√5 : ⅓√1 = √(5/1) = √5  ∛4·∛250-√7·√63 = ∛(4·250)-√(7·63) = ∛1000-√441 = 10-21 = -11 (1⅓)⁻¹ : 2 = (4/3)⁻¹ : 2 = ¾ :2 = 3/8 (√54 : √3) : √2 = √(54/3) : √2 = √18 : √2 = √(18/2) = √9 = 3 √15·√⅗ + ∛20·∛⅖ = √(15·⅗)+∛(20·⅖) = √9+∛8 = 3+2 = 5