Korzystamy ze wzoru: [latex]frac{1}{lambda_n}=R_H(frac{1}{k^2}-frac{1}{n^2}) gdzie:\ lambda_n-dlugosc fali n-tej linii w serii k\ R_H-stala Rydberga=1,097*10^7frac{1}{m}\ k-nr serii\ n-linie danej serii k+1, k+2+...+ k+n[/latex] Seria Lymana rozpoczyna się od k=1. [latex]frac{1}{lambda_2}=R_H(frac{1}{1^2}-frac{1}{2^2})=R_H(1-frac{1}{4})=frac{3}{4}R_H\ lambda_2=frac{4}{3R_H}=frac{4}{3*1,097*10^7frac{1}{m}}=1,215*10^{-7}m=121,5nm\\ ================\ \ 1=R_H(frac{1}{1}-frac{1}{3^2})lambda_3=frac{8}{9}R_Hlambda_3\ lambda_3=frac{9}{8R_H}=1,026*10^{-7}m=102,6nm\ =============\\ 1=R_H(1-frac{1}{4^2})lambda_4=frac{15}{16}R_Hlambda_4\ lambda_4=frac{16}{15R_H}=0,972*10^{-7}m=97,2nm\ Serie Lymana mamy za soba :)[/latex] Teraz bierzemy się za serię Balmera od k=5 [latex]n=6\ 1=(frac{1}{5^2}-frac{1}{6^2})R_Hlambda_6=R_Hlambda_6(frac{1}{25}-frac{1}{36})=R_Hlambda_6(frac{36-25}{900})=R_Hlambda_6frac{11}{900}\ lambda_6=frac{900}{11R_H}=frac{900}{11*1,097*10^7frac{1}{m}}=74,584*10^{-7}m=7,4584mu m\ I tak dalej...[/latex]
