drzewo ma 13m i na jednym końcu 90cm a na drugim 50 cm ile ma kubikow?

Dane: h=13m s1=90cm=0,9m s2=50cm=0,5m Olbicz: V=? Rozwiązanie: [latex]s1=pi R^{2}[/latex] [latex]R^{2}=frac{s1}{pi}[/latex]   [latex]R^{2}=frac{0,9}{3,14}[/latex]   [latex]R^{2} approx 0,29m[/latex]   [latex]R=sqrt{0,29}[/latex]   [latex]R approx 0,54[/latex]   [latex]s2=pi r^{2}[/latex]   [latex]r^{2}=frac{s2}{pi}[/latex]   [latex]r^{2}=frac{0,5}{3,14}[/latex]   [latex]r^{2} approx 0,16[/latex]   [latex]r=sqrt{0,16}[/latex]   [latex]r=0,4m[/latex]   [latex]V=frac{1}{3}pi h(R^{2}+R*r+r^{2})[/latex]   [latex]V=frac{1}{3}*3,14*13(0,54^{2}+0,54*0,4+0,4^{2})[/latex]   [latex]V=frac{1}{3}*3,14*13(0,2916+0,216+0,16)[/latex]   [latex]V=frac{1}{3}*3,14*13*0,6676[/latex]   [latex]V=frac{1}{3}*3,14*8,6788[/latex]   [latex]V approx 9,08m^{3}=9,08kubika[/latex]