Dane: m=7.3 * 10^22 r=384000km=384000000m=384*10^7 T=27,3oby=27d i 3h=648h=2332800s Oblicz: F(d) Rozwiązanie: [latex]T=frac{2pi}{omega}[/latex] [latex]omega=frac{2pi}{T}[/latex] [latex]omega=frac{2*3,14}{2332800}[/latex] [latex]omega=frac{6,28}{2332800}[/latex] [latex]omega=frac{6,28}{2332,8*10^{-4}}[/latex] [latex]omega=frac{6,28}{2332,8*10^{-4}}[/latex] [latex]omega approx 0,0027*10^{-4}[/latex] [latex]omega approx 0,00000027frac{rad}{s}[/latex] [latex]F(d)=momega^{2}r[/latex] [latex]F(d)=7.3 * 10^{22}*0,00000027^{2}*384*10^{7}[/latex] [latex]F(d)=7.3 * 10^{22}*0,729*10^{-14}*384*10^{7}[/latex] [latex]F(d)=7.3*0,729*384*10^{15}[/latex] [latex]F(d)=5,3217*384*10^{15}[/latex] [latex]F(d)=2043,5328*10^{15}[/latex] [latex]F(d)=20435328*10^{11}N[/latex]
