Proszę o pomoc. Pilne na jutro zadania w załączniku. Daje najj..

Zad.1 [latex]frac{(frac{1}{sqrt[3]{8}}+sqrt{49}:2)^2-3,2:sqrt{2frac{14}{25}}}{sqrt{16} cdot (11,25-sqrt[3]{27})^0}}=frac{(frac{1}{2}+frac{7}{2})^2-3,2:sqrt{frac{64}{25}}}{4 cdot 1}=frac{4^2-3,2 cdot frac{5}{8}}{4} = frac{16 - 2}{4}=frac{7}{2}\ \ frac{7}{2} = 14\%\ x = 100\%\ \ x=frac{frac{7}{2} cdot 100}{14}=25 [/latex]   Zad.2 [latex]2,5:1frac{1}{3}+3,75 cdot 4frac{1}{5}-6,25:7frac{1}{7}=frac{5}{2}:frac{4}{3}+frac{15}{4}cdot frac{21}{5}-frac{25}{4}:frac{50}{7}=\ =frac{15}{8}+frac{63}{4}-frac{7}{8}=frac{134}{8}=16,75\ \ 16,75 = 100\%\ x = 4\%\ \ x=16,75 cdot frac{ 4}{100}=0,67[/latex]   Zad.3 [latex]frac{12,75+1frac{2}{3} cdot (-1,4)}{2,2+6frac{2}{15}}=frac{frac{51}{4}+frac{5}{3} cdot (-frac{7}{5})}{frac{11}{5}+frac{92}{15}}=frac{frac{51}{4}-frac{7}{3}}{frac{125}{15}}=frac{frac{125}{12}}{frac{125}{15}}=frac{15}{12}=frac{5}{4}=1,25\ \ 1,25 = 100\%\ x = 20\%\ \ x=1,25 cdot frac{20}{100}=0,25[/latex]   Zad.4 [latex][-3,75]:[(-2frac{1}{3}-3,5):1,75]=[-frac{15}{4}]:[(-frac{7}{3}-frac{7}{2}):frac{7}{4}]=\ =[-frac{15}{4}]:[-frac{35}{6} cdot frac{4}{7}]=-frac{15}{4} : (-frac{10}{3}) = -frac{15}{4} cdot (-frac{3}{10})=frac{9}{8}=1,125\ \ 33frac{1}{3}\% = frac{100}{3}\%\ \ 1,125 = 100\%\ x = frac{100}{3}\%\ \ x=frac{1,125 cdot frac{100}{3}}{100}=0,375 [/latex]   Zad.5 [latex]|frac{(-5frac{1}{3})cdot (-1,8)+9frac{11}{15}}{7,5-2frac{2}{3}}| = |frac{-frac{16}{3} cdot (-frac{9}{5})+frac{146}{15}}{frac{15}{2}-frac{8}{3}}| = |frac{frac{144}{15} + frac{146}{15}}{frac{29}{6}}|=frac{frac{290}{15}}{frac{29}{6}}=4\ \ 4 = 40\%\ x = 100\%\ \ x=frac{4 cdot 100}{40}=10[/latex]   Zad.6 [latex]frac{1frac{2}{3}-sqrt{2frac{1}{4}}}{(-sqrt{1frac{9}{16}}):(-1,2)}=frac{frac{5}{3}-sqrt{frac{9}{4}}}{(-sqrt{frac{25}{16}}):(-frac{6}{5})} = frac{frac{5}{3}-frac{3}{2}}{-frac{5}{4} cdot (-frac{5}{6})}=frac{frac{1}{6}}{frac{25}{24}}=frac{4}{25}=0,16\ \ 0,16 = 2\%\ x = 100\%\ \ x=frac{0,16 cdot 100}{2}=8[/latex]