Dane: [latex] ho=11340 kg/m^3[/latex] a=10cm=0,1m b=10cm=0,1m c=20cm=0,2m Oblicz: p=? Rozwiązanie: [latex]V=a*b*c[/latex] [latex]V=0,1*0,1*0,2[/latex] [latex]V=0,002m^3[/latex] [latex]m=V* ho[/latex] [latex]m=0,002*11340[/latex] [latex]m=22,68kg[/latex] [latex]s=a*b[/latex] [latex]s=0,1*0,1=0,01m^2[/latex] [latex]p=frac{mg}{s}[/latex] [latex]p=frac{22,68*10}{0,01}[/latex] [latex]p=frac{226,8}{0,01}[/latex] [latex]p=22680Pa=22,68kPa[/latex]
dane: a = 10 cm = 0,1 m b = 10 cm = 0,1 m c = 20 cm = 0,2 m d₀ = 11 300 kg/m³ - gęstość ołowiu g = 10 m/s² p max = ? p = F/S F = m·g d = m/V I*V m = V·d V = abc = 0,1m·01m·0,2m = 0,002 m² F = V·d·g = 0,002m²·11300kg/m³·10m/s² = 226 N S min = a·b = 0,1m·0,1 m = 0,01 m² p max = F/S = 226N/0,01m² = 22 600 Pa 1 kPa = 1000 Pa p max = 22,6 kPa ============ Odp. Szukane ciśnienie wynosi 22 600 Pa (22,6 kPa)
