rozwiąż nieróność 3/ IxI-1 >= 2 rozwiąż nierówność f(x+1)

1. [latex]frac{3}{|x|-1}ge2\xin Rsetminus{-1; 1}[/latex]   [latex]1^0\xin(-infty; -1) cup (-1; 0)\frac{3}{-x-1}ge2\2+frac{3}{x+1}le0\frac{2x+2+3}{x+1}le0\(x+1)(2x+5)le0\xin<-frac{5}{2}; -1)[/latex]   [latex]2^0\xin<0; 1) cup (1; infty)\frac{3}{x-1}ge2\frac{3}{x-1}-2ge0\frac{3-2x+2}{x-1}ge0\(x-1)(5-2x)ge0\xin(1; frac{5}{2}>[/latex]     [latex]xin<-frac{5}{2}; -1) cup (1; frac{5}{2}>[/latex]     2. [latex]f(x)=1-frac{2}{x-1}\f(x+1)=1-frac{2}{x}\xin Rsetminus{0; 1}[/latex]   [latex]1-frac{2}{x}<1-frac{2}{x-1}\frac{2}{x-1}-frac{2}{x}<0\frac{2x-2x+2}{x(x-1)}<0\frac{2}{x(x-1)}<0\2>0\x(x-1)<0\xin(0; 1)[/latex]