Oblicz masę cząsteczkową dla szeregu homologicznego alkocholi ( metanol , etanol, propanol, butanol,pentanol)

Metanol CH3OH mCH3OH=12u+4*1u+16u=32u   Etanol C2H5OH mC2H5OH=2*12u+6*1u+16u=46u   Propanol C3H7OH mC3H7OH=3*12u+8*1u+16u=60u   Butanol C4H9OH mC4H9OH=4*12u+10*1u+16u=74u   Pentanol C5H11OH mC5H11OH=5*12u+12*1u+16u=88u

Witam ,    C: 12u H: 1u O: 16u   I.  Metanol: CH₃OH   mCH₃OH: 12u+4u+16u=32u   II. Etanol: C₂H₅OH   mC₂H₅OH: 12u*2+6u+16u=46u   III. Propanol:  C₃H₇OH   mC₃H₇OH=12u*3+8u+16u=60u   IV: Butanol: C₄H₉OH   mC₄H₉OH=4*12u+10u+16u=74u   V. Pentanol C₅H₁₁OH   mC₅H₁₁OH=12*5u+12u+16u=88u