masa jądra izotopu^9 _4 Be wynosi 9,01219u. oblicz deficyt masy tego izotopu u= 1,66*10^-27kg, mp=1,672118-10^-27kgmn= 1,674442*10^-27kg

  Jądro to ma 4 protony i 5 neutronów   m = 9,01219u m₂ = 4 x 1,672118 x 10⁻²⁷kg + 5 x 1,674442 x 10⁻²⁷kg = 15,060682 x 10⁻²⁷kg = 9,0727u   Δm = 9,01219u - 9,0727u = 0,06051u ≈ 0,1 x 10⁻²⁷kg     ---------------------------------------------------------------------------------------------------------- Feci, quod potui, faciant meliora potentes   Pozdrawiam :)