BARDZO WAŻNE NAJLEPIEJ NA DZISIAJ BO JUTRO MAM SPRAWDZIAN Z TEGO !!!

1. Przeskok z 2 na 5: n = 5 k = 2 [latex]E_{25}=A(frac{1}{2^{2}}-frac{1}{5^{2}})=13,6eVcdot0,21=2,86eV=4,58cdot10^{-19}J[/latex]   2. [latex]E=W+Ek[/latex] [latex]Ek=E-W=hv-W[/latex] [latex]Ek=6,63cdot10^{-34}Jcdot scdot 5,4cdot10^{14}Hz-2,11cdot1,6cdot10^{-19}J=[/latex] [latex]=3,58cdot10^{-19}J-3,38cdot10^{-19}J=0,2cdot10^{-19}J[/latex] 3. [latex]E_{32}=frac{hc}{lambda}[/latex]   [latex]lambda=frac{hc}{E_{32}}[/latex]   [latex]lambda=frac{hc}{A(frac{1}{2^{2}}-frac{1}{3^{2}})}=frac{6,63cdot10^{-34}Jcdot scdot 3cdot10^{8}frac{m}{s}}{13,6eVcdotfrac{5}{36}}=frac{19,89cdot10^{-26}Jcdot m}{3,02cdot10^{-19}J}=[/latex] [latex]6,59cdot10^{-7}m=659nm[/latex] 4. [latex]W=4,5eV=7,2cdot10^{-19}J[/latex] [latex]E=W[/latex]   [latex]W=frac{hc}{lambda_{0}}[/latex]   [latex]lambda_{0}=frac{hc}{W}=frac{6,63cdot10^{-34}Jcdot scdot3cdot10^{8}frac{m}{s}}{7,2cdot10^{-19}J}=2,76cdot10^{-7}m=276nm[/latex]